ASTRONOMY A special form of Kepler's Third Law of Planetary Motion is given by a = root(3, P ^ 2) , where a is the average distance of an object from the Sun in AU astronomical unitsand P is the period of the orbit in years. The period of Jupiter's orbit is 12 years. What is its distance from the Sun in AU?

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

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