A map of Rockbridge County has a scale factor of 2.5 in = 5 mi
if the actual distance from Fairfield to Lexington is 12 miles what is the distance on the map?
(plzzz show work I'm doing a test rn thats half my grade pl)

6 inch

Step-by-step explanation:

From the question, we are informed that a map of Rockbridge County has a scale factor of 2.5 in = 5 miles.

When the actual distance from Fairfield to Lexington is 12 miles, the distance on the map will be:

= 12/5 × 2.5

= 2.4 × 2.5

= 6 inch

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

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