Susan’s science class is performing an experiment that involves dropping objects from various heights, starting close to the ground and working upward to 8 feet. The function , where x represents the distance from the ground, represents the time it takes for the object Susan drops to hit the ground. The graph represents the function Identify some of the key features of the graph. That is, determine if the function is monotonically increasing or decreasing, state the end behavior, find the x- and y-intercepts, find the endpoint, and state the domain and the range of the graph (without considering the context).

1) The function is monotonically increasing

2) The end behavior of the function is x tends to infinity as t(x) tends infinity

3) The x and y -intercept is (0, 0)

4) The endpoint is (0, 0)

5) The domain is 0 ≤ x ≤ +∞

The range is 0 ≤ t(x) ≤ +∞

Step-by-step explanation:

1) The given function of the time for the object to hit the ground is t(x) = 1/4·√x

Where;

x = The distance from the ground

t = The time it takes for the object to hit the ground

Monotonically increasing function, we have;

A function that is continuous on [a, b] and it can be differentiated in the domain, (a, b) is monotonically increasing when df(x)/dx > 0 for all values of x in (a, b)

However, where df(x)/dx < 0 for all values of x in (a, b), the function is decreasing

Therefore, using an online tool, we have;

dt(x)/dx = d(1/4·√x)/dx = 1/8 × 1/√x

Therefore, the dt(x)/dx > 0, for 0 < x < +∞ and the function is monotonically increasing

2) The end behavior of the function as x tends to infinity, t(x) = 1/4·√x approaches infinity

3) From the end behavior, and the nature, of the function t(x) = 1/4·√x, where both variables are directly proportional, we have that the x and y -intercept =  (0, 0)

4) The endpoint is (0, 0) given that as t(x) tends to 0, x tends to 0

5) The domain is 0 ≤ x ≤ +∞

The range is 0 ≤ t(x) ≤ +∞.

step-by-step explanation:

30% of $420 is 0.30($420) = $126 and $420 + $126 = $546.

or, 130% of $420 is 1.3($420) = $546.

notice that this is not the $600 original list price with which we started.

why doesn't this work?

the method does not work because 30% of $420 is not the same amount as the 30% of $600. it may seem obvious when stated this way, but it is a very common error made on problems of this type. we cannot just use the same percent and get back to the original amount because we are taking that percent of a different value.

to work problems of this type correctly, it is generally best to write an equation for the situation and then solve.

example: since (100% – 30%)(original price) = (sale price)

70% of the   (original price) is $420.

0.7x   = 420

equation image indicator

x = 600

the original cost was $600.

we may also solve this problem using the two-step method. working the problem in two steps requires us to use more algebra skills. we have to know that x = 1x (identity property of multiplicationtext annotation indicator) and that 1x – 0.3x = 0.7x (subtracting like terms). then we solve the problem as follows:

(original price) – 30%(original price) = sale price

x – 0.3x = 420

0.7x = $420

equation image indicator

x = 600

the original cost was $600.  

note that with both of the above methods we do obtain the correct original amount.

example: after a 5% pay raise, hermione is earning $22,680 per year. what was she earning before the pay raise?

105% of (original salary) = current salary

1.05x = 22,680

equation image indicator

x = 21,600

hermione earned $21,600 per year before the pay raise.

this is an example so maybe you will get how to at least do it!

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.