What is the equation of the line that passes through the point 4,4 and has a slope of 0?

The equation of a line that passes through a point is an algebraic equation. It can also be referred to as the Slope-Intercept Equation.

The equation of the line that passes through the point (4, 4) and has a slope of 0 is written as: y = 4

The equation of the line through a point (x1, y1) can be represented by the algebraic equation:

y = mx + c

where:

m = slope

c = y - intercept

From the question,

(x1, y1) = (4, 4)

m = slope = 0

Substituting these values into the algebraic equation,

4 = (0 x 4) + c

Hence, y = 4

The equation of the line that passes through the point (4, 4) and has a slope of zero is y = 4

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y = 0x + 4 or y = 4.

Step-by-step explanation:

The slope is zero, and in other words, m = 0.

The slope intercept form is y = mx + b.

Replace m with 0.

y = 0m + b.

The y intercept is the y point on the line. Since this slope is a straight horizontal line, the y point given is the y intercept. b is the y intercept.

y = 0m + 4

Since any number times 0 is 0 you can right it as

y = 4.

darn right!

step-by-step explanation:

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