Brainlist! Please help me! TYSM in advance! I'll report if you give false answer. Match each sequence of transformations to the graph that proves shape I is similar to shape II when applied to shape I.
-a reflection across the
y-axis, followed by a
90° clockwise rotation
about the origin, and then
a dilation by a scale factor
of 0.5
-a translation 7 units
right and 4 units down,
and then a dilation
by a scale factor of 2
-a reflection across the
y-axis, followed by a
90° counterclockwise
rotation about the origin,
and then a dilation by a
scale factor of 0.5
-a reflection across the
y-axis, and then
a dilation by a scale
factor of 2

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.