Find two consecutive even integers such that the sum of the numbers is ten more than the larger number. (Must solve algebraically to receive full credit.)

10 and 12

Step-by-step explanation:

Let the smallest number = 2x

Then the larger number is 2x + 2

2x + 2x + 2 = 2x + 2 + 10                     Subtract 2x + 2 from both sides

2x = 10                                                  Divide by 2

x = 5

The smaller number is 2x = 2 * 5 = 10

The larger number is 2x + 2 = 12

answer: a

step-by-step explanation:

6.5

step-by-step explanation:

you said it was in the question

~courtney