The population of a school of fish increases at an annual rate of 18%. there are currently 500 fish in the school. how many fish will there be in 12 years

This is a geometric sequence with the first term 500, common ratio is (100 + 18)/100 = 1.18 and number of terms is 12.

Tn = ar^(n - 1)
T12 = 500 x 1.18^(12 - 1) = 500 x 1.18^11 = 500 x 6.176 = 3,087.96

Therefore, there is 3,088 fishes in the school in 12 years.

The correct one is c.