The length of a rectangular sign is 5 times its width. If the sign’s perimeter is 36 inches, what is the sign’s area?

First you need to find the length. To do this, you need to find what two numbers, when doubled, equal 36. I just tried trial and error until I got to 3. So 3 times 5 equals 15. Then you have two 15's and two 3's which equals 36. Now that you know the length and width you can then find the area. The formula to find area is L*W=A. Following this the expression would be 15*3=45. So the area is 45

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet