X^2-12x+__=(x-__)2
what’s the answer??

The answer is x=0

Step-by-step explanation:

Rewrite the equation as a trinomial.

x 2 + 12 x + 0

Move 0 to the right-hand side.

x 2 + 12 x = 0

Divide the coefficient of the  x

-term by 2, then square the result. Add the result to both sides.

12 /2 = 6 ;6^2   = 36

x 2 + 12 x + 36 = 36

Factor the perfect square trinomial  

x 2 + 12 x + 36

on the left-hand side.

( x + 6 ) 2 = 36

Take the square root of both sides and solve for  x .

√ ( x + 6 )^ 2 = ± √ 36 =

x+ 6 =  ± 6

x =  − 6 + 6 = 0

x =  − 6  − 6 = − 12

Check

If  x = 0 :

( 0 ) ^2 + 12 ( 0 ) = 0

0 = 0

If  x = − 12 :

( − 12 ) ^2 + 12 ( − 12 ) = 0

144 − 144 = 0

0 = 0

right

step-by-step explanation: