the lenght of the floor is 32 m longer than its width and there is greater than 200 square meters. you will cover the floor completely with tiles. what will be the possible dimension of the floor?

Let’s assume the width of the floor is x and the area is a

To figure out the dimensions we need to figure out the value of the variable (x)

This means that the length is xm+32m (the m is for metres) and that the area is a>200m2

Because it says what is the possible dimensions let make the area 201m2

The formula for the area of a rectangle is length times width so the equation we use to figure out the value of x

201=x+x+32

So let’s collect like terms and solve from there
201=2x+32
201-32=2x+32-32
169=2x
169/2=2x/2
84.5=x

Now that we know the value of x is 84.5 we can figure out the length is 116.5m and the width is 84.5m

Therefore the dimensions of the floor is 116.5m by 84.5m