The area of a triangle reduced by the area of the semicircle is ( 48 - 2π ) square meters. The base of the triangle is 12 meters. Find the height of the triangle and radius of the semicircle.

The height of the triangle is 8 meters and the radius of the semi-circle is 2 meters

Step-by-step explanation:

The area of a triangle = × b × h, where

The area of a semi-circle =   π r², where

∵ The area of the figure = Area Δ - Area semicircle

∵ The area of the figure =   × b × h -   π r²

∵ The base of the triangle is 12 meters

→ Substitute it in the area of the figure above

∴ The area of the figure =   × 12 × h -   π r²

∴ The area of the figure = 6h -   π r²

∵ The area of the figure = 48 - 2 π

→ Equate the two expressions of the area of the figure

∴ 6h -   π r² = 48 - 2 π

→ Equate the like terms of the two sides

∵ 6h = 48

→ Divide both sides by 6 to find h

∴ h = 8

∵ - π r² = -2 π

→ Divide both sides by -π

∴    r² = 2

→ Multiply both sides by 2

∴ r² = 4

→ Take √  for both sides

∴ r = 2

The height of the triangle is 8 meters and the radius of the semi-circle is 2 meters

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step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5.1