The length of a rectangle is 4 yd less than three times the width, and the area of the rectangle is 55 ya? Find the dimensions of the rectangle. Length: Width :

length = 11 yard

width =  5 yard

Step-by-step explanation:

Area of a rectangle = L W

where A = 55 yard

           L = 3W - 4

find: Length

        width

solution:

A = L W

55 = (3W - 4) W

55 = 3W² - 4W

3W² - 4W - 55 = 0

use quadratic equation to solve for W:

W = - (-4) ± √(-4)² - 4(3)-55

                    2(3)

W = 5,  W = -11/3

substitute W=5 to equation L = 3W - 4 to solve for L

L = 3W - 4

L = 3(5) - 4

L = 15 - 4

L = 11

therefore, the dimensions of a rectangle:

length = 11 yard

width =  5 yard

step-by-step explanation:

step-by-step explanation: