for r gives us: ![r=\sqrt[3]{\frac{3v}{4\pi}}](/tpl/images/0923/0303/62edc.png)
for v2 gives us: 
![\sqrt[3]{r^3} = \sqrt[3]{\frac{3v}{4\pi}} \\r = \sqrt[3]{\frac{3v}{4\pi}}](/tpl/images/0923/0303/8a9c8.png)
Please at least help me with one of them cause I have no clue.
Solve for r:
Solve for r:...
Mathematics, 23.11.2020 08:00 prince96
Please at least help me with one of them cause I have no clue.
Solve for r:
Solve for r:
Solve for v2
Answers: 2
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