It rained all day on Father's Day and the temperature dropped ten and seven tenth degrees. The next day the rain stopped and the temperature rose twelve and six tenths degrees. If the temperature at the beginning of Father's Day
was sixty five and eight tenths degrees, what was the temperature at the end of the day after Father's Day?
Write numerical answer only (no sentences, no units)
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67.7

Step-by-step explanation:

Temperature at beginning of Father's Day = 65.8 degrees

Drop in temperature because of rain = 10.7 degrees

Rise in temperature after the rain the next day = 12.6 degrees

Therefore, temperature at the end of the day after the Father's Day

= Temperature at beginning of Father's Day minus Drop in temperature because of rain plus Rise in temperature after the rain the next day

= 65.8 - 10.7 + 12.6

= 67.7 degrees

NB: The answer was written as only 67.7 as requested by the questioner.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: