Write a linear equation that passes throug the point (2,-9) and has a slope of -5 in slope-intercept form.

y = -5x +1

Step-by-step explanation:

y+9 = -5(x-2)

y+9 = -5x+10

y     = -5x+1

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )