A set of 4 consecutive odd integers has a sum of 216. What are the integers?

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Step-by-step explanation:

So the four consecutive odd integers are: 51 , 53 , 55 and 57 .

If the first integer is n, then the other three are n+2,n+4 and n+6

and we have:

216=n+(n+2)+(n+4)+(n+6)=4n+12

Subtract 12 from both ends and transpose to get:

4n=204

Divide both sides by 4

to get:

n=51

So the four consecutive odd integers are:

51,53, 55 and 57.

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step-by-step explanation: