N=480×10^9
Write N as a product of powers of its prime factors.

I got 5^10 x 2^14 x 3

Step-by-step explanation:

1. Do a tree to find 480 as a product of its prime factors

2. You should get 480= 5x2x3x2x2x2x2

3. 10 expressed as a product of its prime factors is 5x2

4. so 10^9 expressed as a product of its prime factors would be

5x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2

5. You can then write out 480x10^9 as a product of its prime factors

5x2x3x2x2x2x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2

6. change this to use powers

5^10 x 2^14 x 3

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions