Not sure how to answer this, a explanation would be appreciated!

I'm going to assume normal form is slope-intercept form by the way.

x=2;y=4. Written in a coordinate would be (2,4)

Normal forms; y=-x+6 and y= 4x-4

Explanation: it's a system of equations so if

y=-x+6 and y=4x-4 then -x+6=4x-4 (because they're both equal to y)

From there it's easy.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

step-by-step explanation: