What are the values of a, b, and c in the quadratic equation –2x2 + 4x – 3 = 0?

the value of constants are a = - 2, b = 4 and c = -3

Step-by-step explanation:

The general quadratic equation is q(x) = ax² + bx + c where a,b and c are constant and a ≠0

The given quadratic equation is -2x² + 4x - 3

To obtain the values of a, b and c by compare the general equation with -2x² + 4x - 3

now compare the ax² + bx + c with -2x² + 4x - 3

so, values are  a = - 2, b = 4 and c = -3

Therefore, the value of constants are a = - 2, b = 4 and c = -3

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)