Suppose cot(theta) = 5/12, where pi < theta < 3pi/2. What is sin(theta)? A. -12/13
B. -5/13
C. 5/12
D. 12/13

- 12 /13

Step-by-step explanation:

Given that:

Cot(θ) = 5 /12 ;

Recall ; cot θ = 1 / tan θ ; tan θ = sin θ / cos θ

Hence ;

tan θ = 1 / cot θ

tan θ = 1 ÷ (5 / 12)

tan θ = 1 * 12 /5 = 12/5

Tan θ = opposite / Adjacent = 12 /5

Sin θ = opposite / hypotenus

Hypotenus = √(opposite² + adjacent²)

Hypotenus = √12² + 5²

Hypotenus = √(144 + 25)

Hypotenus = √169

Hypotenus = 13

Hence,

Sin θ = opposite / hypotenus = 12 / 13

pi < theta < 3pi/2 lies in the 3rd quadrant ; SinΘ will be negative ;

Sin θ = - 12 /13

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof