If Gabe's Soccer Ball Company is able, due to competitive pressure, to charge $60 for a new soccer ball, while one soccer ball costs $28 to make, plus $15,000 per month in overhead costs (mostly Gabe's extravagant salary) find: a. The average cost c(x) of producing each soccer ball b. Algebraically find the number of soccer balls Gabe's company must produce per month in order to break even (Profit = 0). Profit = Total Revenue – Total Cost c. Algebraically find the number of soccer balls Gabe's company must make to earn a profit of $10,000 per month. d. If Gabe took a pay cut to reduce the overhead costs to $8,000 per month, how many fewer balls would the company have to sell to break even. (There are multiple ways to get this result).

Results are below.

Step-by-step explanation:

Giving the following information:

Selling price= $60

Unitary variable cost= $28

Fixed costs= $15,000

First, we need to calculate the average total cost:

Average cost= total cost / number of units

For example, for 1 unit and 10,000 units:

1 unit:

Average cost= 15,028/1 = 15,028

10,000 units:

Average cost= (15,000 + 28*10,000) / 10,000

Average cost= $29.5

Now, we can calculate the break-even point in units:

0= (60*x) - (28*x) - 15,000

x= number of units to break-even

0= 32x - 15,000

15,000/32= x

468.75=x

break-even point in units= 469

For the desired profit of $10,000:

10,000 = (60*x) - (28*x) - 15,000

25,000= 32x

781.25= x

Break-even point= 782 units

Finally, fixed costs dropped by $8,000:

0= 32x - 7,000

x= 7,000/32

x= 218.75

Break-even point= 219

Difference= 250 units

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".