Some of Amber's daily activities are listed here. Use these descriptions to select the word or symbol that correctly completes each sentence. • Amber spends 3/16 of each day doing homework. • Amber spends 0.25 of each day at school. • Amber spends 1/3 of each day sleeping. (A) 3/16 of a day 0.25 of a day (B) 0.25 of a day 1/3 of a day (C) Amber spends time doing homework than she does at school. (D) Amber spends time sleeping than she does at school.

(D) Amber spends time sleeping than she does at school.

Step-by-step explanation:

Given that :

• Amber spends 3/16 of each day doing homework.

• Amber spends 0.25 of each day at school.

• Amber spends 1/3 of each day sleeping.

Hence,

Amber spends 0.1875 of a day doing homework, which is (0.1875 * 24) = 4.5 hours

0.25 of each day at school ; (0.25 * 24) = 6 hours

1/3 of each day sleeping ; (1/3 * 24) = 8 hours

Time spent sleeping = 8 hours

Time spent in school = 6 hours

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)