Assume that emergency medical personnel in California are planning for future resources and it has been observed that the average number of traffic accidents requiring ambulance assistance on the Hollywood Freeway between 7 and 8 AM on Wednesday mornings is 1.1. What, then, is the probability that there need for exactly 2 ambulances on the Freeway during that time slot on any given Wednesday morning?

Answer is 0.5

Step-by-step explanation:

The text implies that the number of traffic accidents determines the number of ambulances required on the road. Hence, 1 traffic accident requires 1 ambulance.

The time slot and time of day remain same in both the text and the question.

The average or mean number of accidents is 1.1

QUESTION: What then is the probability that there is need for exactly 2 ambulances on that road and in that time frame?

In other words, what is the probability that there'll be 2 accidents on that road and in that time frame?

Since the mean number of accidents is 1.1,  2 is above the mean.

Probability of 1.1 accidents is 1, since that's the mean (expected value).

Probability of 2 accidents is 1/2 which is = 0.5

step-by-step explanation:

step-by-step explanation:

hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45