Jane is a computer science major planning to take 4 courses next semester. She is planning to take 2 computer science courses and 2 courses from other areas. How many different schedules can she build?

24 schedules.

Step-by-step explanation:

Given data:

Courses planning to take = 4

Computer courses = 2

Courses from other areas = 2

Solution:

This problem can be solved using permutation.

For Computer science courses.

npr = n! / ( n - r )!

Where n = 4

r = 2

4p2 = 4!/( 4-2)!

= 4!/2!

= 12

For other courses.

Where n = 4

r = 2

4p2 = 4!/( 4-2)!

= 4!/2!

= 12

Jane can have a total of 24 different schedules.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

what is the original number? you forgot to add it.