If a football is thrown upward, its height above the ground is given by the equation s=-16t^2+Vot+so, where

Vo and so are the initial velocity and intial height of the

Football, respectively, and t is the time in seconds. suppose

the football is thrown from the top of a building that is

192 feet tall, with an initiae speed of 96 feet per second.

a)write the polynomial that gives the height of the Football in terms

of the variable t (time)

b) what is the height of the Football after 2 seconds have

Clapsed? Will the football hit the ground after 2 seconds?

a) s = -16 + 192t + 96

b) Height of the football after 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

Step-by-step explanation:

Given:

s = -16 + t +

where: s is the height of the football above the ground, t is the time, is the initial velocity and is the initial height.

The height of the building = = 192 feet and the initial speed of the ball = = 96 feet per second, then;

s = -16 + 192t + 96

a) The polynomial is given as:

s = -16 + 192t + 96

b) The height of the football when t = 2 seconds is;

s = -16(2) + 192(2) + 96

 = -32 + 384 + 96

 = -32 + 480

s = 448

The height of the football when t = 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

answer: i believe it’s 245.04

step-by-step explanation: