1. A machine shop has eight screw machines but only three spaces available in the production area for the machine. In how many different ways can the eight machines be arranged in the three spaces available? 2. A quality control randomly selects two of five parts to test for defects. In a group of five parts, how many combinations of two parts can be selected?

a= 336 different ways

b= 10 possible combinations

Step-by-step explanation:

As it is a definite machine and it must have ordered combinations therefore it is a permutation question . So finding 3 out of eight

8 P 3= 336  different ways the eight machines be arranged in the three spaces available.

Since the parts are randomly selected and there is no distinct pattern therefore combinations is used to solve this.

5C2 = 10 possible combinations of two parts can be selected.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

5.25 ounces

step-by-step explanation:

divided 3/4 and 6