Little help here guy

Calculate volume

Answer/Step-by-step explanation:

Problem 1:

Radius = 4.8 cm

Height = 6 cm

Volume of cylinder (V) = πr²h

Plug in the values

V = π*4.8²*6 = 434.29 cm³

Problem 2:

Length of pipe = 26 cm

Internal diameter = 6.5 cm

Thickness = 0.5 cm

Pipe volume (V) = π(R² - r²)h

where,

R = Outer radius = ½(6.5) + 0.5 = 3.75 cm

r = inner radius = ½(6.5) = 3.25 cm

h = height = 26 cm

Plug in the values

V = π(3.75² - 3.25²)*26 = 285.88 cm³

Problem 3:

Volume the cylindrical paint can hold = 2.5 litres = 2.5*1000 = 2,500 cm³

Height (h) = 16 cm

Radius (r) = ??

Volume of cylindrical can (V) = πr²h

Plug in the values

2,500 = π × r² × 16

2,500 = 16π × r²

Divide both sides by 16π

2500/16π = r²

49.7 = r²

Take the square root of both sides

√49.7 = r

r = 7.05 cm (nearest hundredth)

Problem 4:

The section of the guttering is ½ of a cylinder

Diameter = 14 cm = 0.14 m

Radius = ½(0.14) = 0.07 m

Volume = 20 litres = 0.02 m³

Length (h) = ??

Volume of the guttering = ½(volume of cylinder) = ½(πr²h)

Plug in the values

0.02 = ½(π*0.07²*h)

0.02*2 = 0.0049π*h

0.04 = 0.0049π*h

Divide both sides by 0.0049π

0.04/0.0049π = h

2.6 = h (nearest tenth)

Length = 2.6 m

Problem 5:

Height of the smaller cylinder (h) = 13 cm

Radius of the smaller cylinder (r) = ½(7) = 3.5 cm

Volume of smaller cylinder = πr²h = π × 3.5² × 13 = 500.3 cm³

Volume of larger cylinder filled to a height of 5 cm = Volume of smaller cylinder

Thus:

Volume of cylinder filled to height of 5cm = 500.3 cm³

height (h) = 5

radius (r) = ???

Therefore,

500.3 = π × r² × 5

500.3 = 5π × r²

500.3/5π = r²

31.9 = r²

√31.9 = r

r = 5.6 cm (nearest tenth)

the answer is 2/54

step-by-step explanation:

d. corresponding side lengths in similar triangles are proportional in length.

step-by-step explanation: