IM GANNA FAIL PLS HELP IDK WHAT THE BOXES R FOR HELPP PLS I BEG YOU (I will give u 100 points on the next question and brain list)

Boxes are to do your multiplication

2. Estimation = 550  Actually = 570  3.   Estimation = 1,900  Actually = 1884

4. Estimation =  24050  Actually =  24073

Hope this helps have a blessed day

Step-by-step explanation:

1) 274. For this you just have to do 7x2 which is 14 then you carry the one above the three then 3x2 which is 6 plus the one you carried so 7 then2x1 which is 2 so you get 274.

2) 570. For this one you do 3x0 which is 0. The reason for this is because anything multiplied by 0 is 0. then you do 3x9 which is 27 so you carry the 2 above the one you go from right to left so that is 3x1 which is 3 then add the two you carried which is 5 which gives you a total of 570.  

3) for this one you do 1x4 which is 4 then you do 7x4 which is 28so you carry the two over to the 4 then multiply 4x4 which gives you 16 then add the 2 which is 18 so that gives you a total of 1,884 and the 4th I will solve the 4th that is 24,073 you get that by doing 7 x9 which gets you 63 so you carry the 6 to the three next to it then you do 7x3 which is 21+3 which is 24 then carry the 2 to the 4 then do 7x4 which is 28 + the 2 you carried which is 30 so you leave the 0 and carry over the 3 then 7x3 which is 21+ the three which got carried over is 24 which gets you a total of 24,073

step-by-step explanation:

b and c

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

=====================================

part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

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part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).