• To round a number, look at the digit to the right of the Chapter
place value to which you are rounding.
1
• If the digit is 5 or more, round up.
• If the digit is less than 5, round down.
Round up
Add 1 to the
146 rounded to the nearest ten is 150.
number in the place
value to which you
This is the Since 6 is greater than 5, round the
are rounding.
tens place. 4 up to 5.
Make the digits to
the right of it o.
45.23 rounded to the nearest tenth is 45.20.
Round down
Do not change the
number in the place
This is the Since 3 is less than 5, the 2 stays the
value to which you
tenths place. same.
are rounding.
Make the digits to
2. Underline the tens digit. Round to the nearest ten.
the right of it o.
a) 36
b) 162
c) 105
3. Underline the hundreds digit. Round to the nearest hundred.
a) 732
b) 675
C) 1825
4. Underline the tenths digit. Round to the nearest tenth.
a) 0.37
b) 74.55
c) 15.23
5. Underline the hundredths digit. Round to the nearest hundredth.
a) 1.212
b) 3.427
c) 0.351

2. A) 37 B)160 C) 110

The tens digit is 10,20,30,40,50,60,70,80,90. Two away to the left of a decimal point.

3. A)730 B) 675 C)1930

The hundreds digit is three from the left of a decimal point.

4. A) 0.40 B)74.60 C)15.20

The tenth is one away to the right of the decimal.

5. A)1.210 B) 3.430 C)0.350

The hundreth is two away to the right of the decimal point.

Explanation:

If it is above 5 you bring the digit before it up by one, if it is under 5 you bring the digit that is under 5 to zero.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180