1 litre of a liquid P has a mass of p grams. 1 Litre of a liquid Q has a mass of q grams. A liquid R is made by mixing a volume of liquid P with a volume of liquid Q in the ratio 3:7. Find an expression, in terms of p and q, for the mass of 50 litres of liquid R

mass of 50 L of R = 15p + 35q

Step-by-step explanation:

1L of P = p g

1L of Q = q g

R = 3P + 7Q

total = 10

P = 3/10 R

Q = 7/10 R

R = 50 L

50 L × 0.3 = 15 L the amount of P in L

15 L of P = 15p g

35 L 0f Q = 35 q g

then

mass of 50 L of R = 15 p + 35 q grams

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step-by-step explanation:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1