Find the equation of the line that passes through points a and b.
Please help.

y=2x-1

Step-by-step explanation:

Gradient : (7-3) / (4-2) = 2

y=2x+c

substitute one of the points

3=2*2+c

c=-1

y=2x-1

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2