A, B, C and D are points on the circumference of a circle, centre O. ED is a tangent to the circle.

E

Angle ODB = 25°

А

Work out angle BAD.

You must give a reason for each stage

of your working.

250

D

B

С

Total marks: 4

PLEASE HELPPP

Angle at BAD = 115°

Step-by-step explanation:

Angle at ODB = 25°

Step 1: Joining point B to the centre of the circle gives an equilateral triangle

Angle at OBD = 25° (base angles of an equilateral triangle are equal)

Angle at BOD = 180° - (25° + 25°) = 130° (sum of angles of a triangle = 180°)

Reflex angle at BOD = 360° - 130° = 230° (sum of angles at a point = 360°)

Step 2: Joining point B to A and point D to A gives another triangle

Angle at BAD = ½ × 230° = 115° (angle at centre is twice the angle at any point on the circumference)

Therefore, angle at BAD = 115°

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x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1