A builder was building a fence. In the morning, he worked for 25 of an hour. In the afternoon, he worked for 910 of an hour. How many times as long as in the morning did he work in the afternoon? Write a division equation to represent this situation, then answer the question.

9514 1404 393

  (9/10)/(2/5) = ratio of work times

  2 1/4 times as long

Step-by-step explanation:

Given:

  2/5 hours work in the morning

  9/10 hours work in the afternoon

Find:

  an equation for how many times as long was afternoon work compared to morning work

  the equation solution

Solution:

  a/m = r . . . . ratio of afternoon work to morning work

  (9/10)/(2/5) = r . . . equation

  (9/10)/(4/10) = r

  9/4 = r = 2 1/4 . . . solution

The builder worked 2 1/4 times as long in the afternoon as in the morning.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

2x^2+5x+17

your welcome. : )