A football team needs to move the ball at least 10 yards forward from the original starting point in order to get a first down. Angel runs for 6 yards on the first play. On the second play, he is sacked for −9 yards. At least how many yards does his team need on the third play to get a first down?

13 yards

Step-by-step explanation:

Required distance moved from original position should be ≥ 10 yards in other to get a first down.

Run on first play = 6 yards

Second play = - 9yards

The least number of yards needed on third play :

Let yard needed on third play = x

First play + second play + third play = 10

6 + (-9) + x = 10

6 - 9 + x = 10

-3 + x = 10

x = 10 + 3

x = 13 yards

At least 13 yards is needed on third playbto get a first down.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!