In the triangle shown, let AB = DE, BC = EF, and CA = FD. Use Rigid Motions to show (triangle)ABC onto (triangle) DEF.

Step-by-step explanation:

Given: AB≅DE, BC≅EF, CA≅FD

Since those are the given it is maped A to D, B to E, C to F

This is a rigid transformation because the distance is preserve (givens) and the triangle ABC is map to triangle DEF.

Rigid transformations produce congruent figures so triangle ABC is congruent to triangle DEF

the first option is the answer.

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step-by-step explanation: