A triangle has vertices on a coordinate grid at P(-10,1)P(−10,1), Q(-10,-7)Q(−10,−7), and R(-5,-7).R(−5,−7). What is the length, in units, of \overline{PQ} PQ



?

Step-by-step explanation:

Given the following coordinates of a triangle

P(-10,1)

Q(-10,-7)

R(-5,-7)

Required

Length of PQ

PQ = √(y2-y1)²+(x2-x1)²

From the coordinate;

x1 = -10, y1 = 1, x2 = -10 y2 = -7

Substitute

PQ = √(-7-1)²+(-10-(-10))²

PQ = √(-8)²+0²

PQ = √64

PQ = 8units

Hence the length of PQ in units is 8units

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: