In △JKL, MO=23 in. What is the length of KO⎯⎯⎯⎯⎯⎯? Enter your answer in the box An obtuse triangle J K L is drawn. N is the midpoint of side J K. Segment J N and segment N K are labeled with double tick mark. P is the midpoint of side K L. Segment K P and segment P L are labeled with single tick mark. M is the midpoint of side L J. Segment L M and segment J M are labeled with triple tick mark. Line segment J P and K M and L N are medians of the triangle. Medians intersect with each other at an interior point labeled as O.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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