10 .find the partial sum S10 of the arithmetic series with a1 = 4, d = 5.

S10 = 320

Step-by-step explanation:

The formula for calculating the sum of the nth term of an AP is expressed as

Sn = n/2(2a+(n-1)d))

Given

a = 4

d = 5

n = 10

S10 =10/2{2(5)+(10-1)5}

S10 =5{10+9(6)}

S10 =5{10+54}

S10 = 5(64)

S10 = 320

Hence the sum of the first ten terms of the sequence is 320

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours