How do I solve this and check all the solutions?

x = 2

Step-by-step explanation:

(Square both sides)

20 - 8x = x^2

(Solve 20 - 8x = x^2)

x = 2 , x = 10

x = 10 is false, so the answer is x = 2.

x=2

Step-by-step explanation:

√20-8x=x

2√5-2x=x (by simplfing redical expression)

4(5-2x)=x^2 (square both side)

20-8x=x^2

20-8x-x^2=0

-x^2-8x+20=0

x^2+8x-20=0

x=2

Note:There is a another answer x=-10 But it's wouldn't fit out with this equation

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2