The vertices of a triangle are A(-2, 1), B(2, 2) and C(6, - 2). Find the equation of the altitude of AD drawn from A to BC.

The equation of altitude AD drawn from A to BC will be:

Step-by-step explanation:

Let m₁ and m₂ be the slope of line AD and BC respectively.

Now, AD⊥BC

∴ m₁ × m₂ = -1

be the slope of line AD and BC respectively.

⇒ m₁ = -1/m₂    → (A)

Finding the slope of BC using points

B(2, 2)

C(6, - 2)

On substituting the value of m₂ in equation (A)

m₁ = -1/m₂

    = -1/(-1)

    = 1

We know that the point-slope form of the line equation is

∴ Equation of altitude AD passing through A(-2, 1) with slope 1 will be

Therefore, the equation of altitude AD drawn from A to BC will be:

d

step-by-step explanation:

d

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation: