Chloe wants to divide 600 jellybeans into equal groups. She wants each group to have more than 10 jellybeans, but less than 100. What are three possible groupings Chloe can make?

One group made up  of 12 can each have 50.=600

the second group of 30 can each have 20=600

third group made of 15 can each have 40=600

Step-by-step explanation:

not sure if this is correct, but...

you could do 12 groups of 50

or 14 groups of 60

orrr 20 groups of 30

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are