Suppose that the weight (in pounds) of an airplane is a linear function of the amount of fuel (in gallons) in its tank. When carrying 18 gallons of fuel, the airplane weighs 2217 pounds. When carrying 44 gallons of fuel, it weighs 2386 pounds. How much does the airplane weigh if it is carrying 60 gallons of fuel?

You have two points relating fuel and weight.

(15,2187) and (35,2303)

slope = (2303-2187)/(35-15) = 5.8

intercept = ?

2187 = 5.8*15 + b

b = 2100

Equation:

f(x) = 5.8x + 2100

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f(50) = 2390 lbs.

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752