Hi. I need help with these questions.
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a = 3, b = 2

Step-by-step explanation:

GivenP(x) = ax² + bx + 1P(1) = 6 and P(-1) = 2To find Values of a and bSolution

Substitute the values of x:

P(1) = 6

6 = a(1)² + b(1) + 16 = a + b + 1a + b = 5

P(-1) = 2

2 = a(-1)² + b(-1) + 12 = a - b + 1a - b = 1a = b + 1

Substitute a in the previous equation:

a + b = 5b + 1 + b = 52b = 4b = 2

Then finding a:

a = b + 1a = 2 + 1 a = 3

So a = 3, b = 2