An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 99 type K batteries and a sample of 100 type Q batteries. The type K batteries have a mean voltage of 8.50, and the population standard deviation is known to be 0.423. The type Q batteries have a mean voltage of 8.76, and the population standard deviation is known to be 0.221. Conduct a hypothesis test for the conjecture that the mean voltage for these two types of batteries is different. Let μ1 be the true mean voltage for type K batteries and μ2 be the true mean voltage for type Q batteries. Use a 0.05 level of significance.

step-by-step explanation:

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

25.3

step-by-step explanation:

1st step

add 3+6

=9

multipy 9*3

=37

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