Factor the expression. 10g^3 12g^2 – 15g – 18
a.(2g2 – 6)(5g 3)
b.(2g2 6)(5g – 3)
c.(2g2 3)(5g – 6)
d.(2g2 – 3)(5g 6)

10g^3 + 12g^2 - 15g - 18 = 2g^2(5g + 6) - 3(5g + 6) = (2g^2 - 3)(5g + 6)

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )