Adam is d years old and Brandon is b old and Brandon is b years older than Adam.
In how many years will Brandon be twice as old as Adam is now?

-b years from now

Step-by-step explanation:

The age of Adam = d

The age of Brandon = b

The number of years Brandon is older than Adam = b

Therefore;

b = d + b

∴ d = 0

Therefore, Brandon will be twice as old as Adam is now when Brandon is 2 × 0 = 0 years

The number of years before Brandon will be twice as old as Adam is now  = 0 - b = -b years from now

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