Jordan throws a ball from a cliff 12 feet above the ground with an initial velocity of 32 feet per second. In the following functions, h(t) represents the height of the ball above the ground, in feet, with respect to time, t, in seconds, after the ball was thrown. Which of the following functions models the amount of time the ball is in the air? h(t)= -4(t-1)^2 +3
h(t)= -16(t-1)^2 -4
h(t)= -16(t-1)^2 +12
h(t)= -16(t-1)^2 +28

Your answer will be the third function

Step-by-step explanation:

The base function you need to know is h(t)= 1/2at^2

Your acceleration in this problem is going to be gravity which they give to you, 32 feet per second squared. Since the ball is falling, it means it will have negative acceleration. Now you have the equation h(t)= -16t^2. The final step is to add the initial height from which the ball was dropped giving you: h(t)= -16t^2 +12

a² + b²= c²

24² + 7² = c²

c= 25

true

explanation: