What is the equation of the line? a. y= -1/2x+1/2
b. y= -2/1x+1
c. y= -1/2x+1
d. y= -2/1x+1/2

A) y = -1/2x + 1/2

Step-by-step explanation:

Find the y-intercept(when x = 0), which is 1/2.

Find the slope: m = y2-y1 / x2-x1

I used points: (3, -1), (-3,2)

m = 2 - (-1) / -3 - 3

m = 3 / - 6

m = -1/2

plug this into the slope intercept form equation: y = mx + b

y = -1/2x + 1/2

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3