-9x+2> 18 \quad \maroonC{\text{ AND}} \quad 13x+15\leq-4−9x+2>18 AND13x+15≤−4minus, 9, x, plus, 2, is greater than, 18, start color #ed5fa6, start text, space, A, N, D, end text, end color #ed5fa6, 13, x, plus, 15, is less than or equal to, minus, 4 Choose 1
Choose 1

(Choice A)
A
x\leq-\dfrac{19}{13}x≤−
13
19

x, is less than or equal to, minus, start fraction, 19, divided by, 13, end fraction

(Choice B)
B
x<-\dfrac{16}{9}x<−
9
16

x, is less than, minus, start fraction, 16, divided by, 9, end fraction

(Choice C)
C
-\dfrac{16}{9} 9
16

13
19

minus, start fraction, 16, divided by, 9, end fraction, is less than, x, is less than, minus, start fraction, 19, divided by, 13, end fraction

(Choice D)
D
There are no solutions

(Choice E)
E
All values of xxx are solutions

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

c. (3,2,6) is the answer.

answer: haha (: i’ll go see what it is

step-by-step explanation:

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step-by-step explanation:

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