Layla has a coin that has a 60%, percent chance of showing heads each time it is flipped. She is going to flip the coin 5 times. Let X represent the number of heads she gets. What is the probability that she gets more than 3 heads?

0.33696

Step-by-step explanation:

Given that:

Probability of showing up head (p) = 0.6

Number of flips = number of trials = 5

Probability of getting more than 3 heads

P(x = x) = nCx * p^x * (1 - p)^(n-x)

P(x> 3) = p(4) + p(5)

P(x = 4) = 5C4 * 0.6^4 * 0.4^1 = 0.2592

P(x = 5) = 5C5 * 0.6^5 * 0.4^0 = 0.07776

Hence,

0.2592 + 0.07776

= 0.33696

Following are the calculation to the probability:  

The probability to see the head

Amount of flips = amount of tries = 5

Chances of getting and over three heads:

Hence,

Therefore, the final answer is "0.34"

Learn more about the probability:

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c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.